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09/10/2021 11:29 am
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At a certain temperature, only 50% HI is dissociated into H2 and I2 at equilibrium. The equilibrium constant is:
(a) 1.0
(b) 3.0
(c) 0.5
(d) 0.25
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09/10/2021 11:34 am
Correct answer: (a) 1.0
Explanation:
HI ⇌ \(\frac{1}{2}\)H2 + \(\frac{1}{2}\)I2
at t = 0 0 0 0
at eq. (1-0.5) (0.5) (0.5)
(∵ α = \(\frac{50}{100}\) = 0.5)
Now KC = \(\frac{(0.5)^{\frac{1}{2}}(0.5)^{\frac{1}{2}}}{0.5}\) = 1