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19/10/2021 11:19 am
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At 298K a 0.1 M CH3COOH solution is 1.34 % ionized. The ionization constant Ka for acetic acid will be
(a) 1.82 × 10-5
(b) 18.2 × 10-5
(c) 0.182 × 10-5
(d) None of these
1 Answer
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19/10/2021 11:27 am
Correct answer: (a) 1.82 × 10-5
Explanation:
Ka = cα2 = 0.1 x \(\Big(\frac{1.34}{100}\Big)^2\)
= 1.82 × 10-5