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Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate (Ka = 1.0 × 10^-5) will be:
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11/10/2021 4:06 pm
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Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate (Ka = 1.0 × 10-5) will be:
(a) 5.0
(b) 6.0
(c) 8.0
(d) 9.0
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11/10/2021 4:10 pm
Correct answer: (d) 9.0
Explanation:
Sodium acetate is a salt of strong base and weak acid.
∴ pH = 7 + \(\frac{1}{2}\)pKa + \(\frac{1}{2}\) log c
where pKa = -logKa = -log 10-5
= 5
logc = log 10-1 = -1
pH = 7 + \(\frac{5}{2}\) - \(\frac{1}{2}\) = 9.0
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