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Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate (Ka = 1.0 × 10^-5) will be:

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Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate (Ka = 1.0 × 10-5) will be:

(a) 5.0

(b) 6.0

(c) 8.0

(d) 9.0

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Correct answer: (d) 9.0

Explanation:

Sodium acetate is a salt of strong base and weak acid.

∴ pH = 7 + \(\frac{1}{2}\)pKa + \(\frac{1}{2}\) log c

where pKa = -logKa = -log 10-5

= 5

logc = log 10-1 = -1

pH = 7 + \(\frac{5}{2}\) - \(\frac{1}{2}\) = 9.0

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