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A solution of 0.1 M NaZ has pH = 8.90. The Ka of HZ is

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A solution of 0.1 M NaZ has pH = 8.90. The Ka of HZ is

(a) 6.3 × 10-11

(b) 6.3 × 10-10

(c) 1.6 × 10-5

(d) 1.6 × 10-6

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Correct answer: (c) 1.6 × 10-5

Explanation:

NaZ is salt of WA/SB

∴ pH = \(\frac{1}{2}\)(pKw + pKa + logC)

8.9 x 2 = 14 + pKa + log0.1

17.8 = 14 + pKa - 1

pKa = 4.8

Ka = Antilog(-4.8)

= 1.585 x 10-5 = 1.6 x 10-5

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