Notifications
Clear all
Equilibrium
1
Posts
2
Users
0
Likes
223
Views
0
11/10/2021 3:59 pm
Topic starter
8 mol of AB3(g) are introduced into a 1.0 dm3 vessel. If it dissociates as
2AB3(g) ⇌ A2(g) + 3B2(g)
At equilibrium, 2 mol of A2 are found to be present. The equilibrium constant of this reaction is
(a) 2
(b) 3
(c) 27
(d) 36
1 Answer
0
11/10/2021 4:04 pm
Correct answer: (c) 27
Explanation:
2AB3(g) ⇌ A2(g) + 3B2(g)
at t = 0 8 0 0
at eq. (8 - 2 x 2) 2 3 x 2
= 4 2 6
Now,
KC = \(\frac{[A_2][B_2]^3}{[AB_3]^2}\)
= \(\frac{\frac{2}{1 \times [\frac{6}{1}]^3}}{[\frac{4}{1}]^2}\) = 27