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18/10/2021 12:20 pm
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20 mL of 0.2 M NaOH are added to 50 mL of 0.2 M CH3COOH (Ka = 1.8 x 10-5) the pH of the solution is
(a) 4.56
(b) 4.73
(c) 9.45
(d) 6.78
1 Answer
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18/10/2021 12:28 pm
Answer is (a) 4.56
Explanation:
NaOH + CH3COOH ⇌ CH3COONa + H2O
20x0.2 50x0.2 0 0
4 10 0 0
0 6 4 4
Conc. = \(\frac{Millimoles}{Total\;Volume}\)
[CH3COOH] = \(\frac{6}{70}\); [CH3COONa] = \(\frac{4}{70}\)
pH = -log 1.8 x 10-5 + log \(\frac{\frac{4}{70}}{\frac{6}{70}}\)
pH = 4.56
This post was modified 3 years ago by admin