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[Solved] The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 ΔG°. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 x 10^-3 S cm^-1.
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18/01/2022 5:44 pm
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The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 ΔG°. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 x 10-3 S cm-1.
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18/01/2022 5:46 pm
Given, Conductivity, ΔG° = 0.146 × 10-3 S cm-1
Resistance, R = 1500 ΔG°
∴ Cell constant = ΔG° × R
= 0.146 × 10-3 × 1500
= 0.219 cm-1
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