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18/01/2022 5:36 pm
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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm-1. Calculate its molar conductivity.
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18/01/2022 5:40 pm
ΔrG° = 0.0248 S cm-1
c = 0.20 M
∴ Molar conductivity, Λm = \(\frac{K \times 1000}{c}\)
= \(\frac{0.0248 \times 1000}{9.2}\)
= 124 S cm2 mol-1