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10/01/2022 5:50 pm
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The cell in which the following reactions occurs:
2Fe3+(aq) + 2I-(aq) → 2Fe2+(aq) + I2(s) has Eocell = 0.236 V at 298 K.
Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction.
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10/01/2022 5:58 pm
Here, n = 2,Eocell = 0.236 V, T = 298 K
We know that:
ΔrG⊖ = -nFE⊖cell
= 2 × 96487 × 0.236
= -45541.864 J mol-1
= -45.54 kJ mol-1
Again, ΔrG⊖ = -2.303 RTlog Kc
⇒ log Kc = \(\frac{Δ_rG^⊖}{2.303 \ RT}\)
= - \(\frac{-45.54 \times 10^3}{2.303 \times 8.314 \times 298}\)
= 7.981
∴ Kc = Antilog (7.981)
= 9.57 × 107