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How would you determine the standard electrode potential of the system Mg^2+ | Mg?

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How would you determine the standard electrode potential of the system Mg2+ | Mg?

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The standard electrode potential of Mg2+ | Mg can be measured with respect to the standard hydrogen electrode, represented by Pt(s), H2(g)(1 atm)| H+(aq)(1M).

A cell, consisting of Mg | MgSO4(aq, 1M) as the anode and the standard hydrogen electrode as the cathode, is set up.

Mg|Mg2+ (aq, 1M)||H+ (aq, 1M)|H2(g, 1 bar), P(t)

Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.

\(E^{\ominus} = E^{\ominus}_R - E^{\ominus}_L\)

Here, \( E^{\ominus}_R\) for the standard hydrogen electrode is zero.

∴ \(E^{\ominus} = 0 - E^{\ominus}_L\)

= \(- E^{\ominus}_L\)

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