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How much electricity in terms of Faraday is required to produce (i) 20.0 g of Ca from molten CaCl2. (ii) 40.0 g of Al from molten Al2O3.
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21/01/2022 4:46 pm
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How much electricity in terms of Faraday is required to produce
(i) 20.0 g of Ca from molten CaCl2.
(ii) 40.0 g of Al from molten Al2O3.
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21/01/2022 4:51 pm
(i) According to the question,
Ca2+ + 2e- → Ca (40 g)
Electricity required to produce 40 g of calcium = 2 F
Therefore, electricity required to produce 20 g of calcium = \(\frac{2 \times 20}{40}\)F
= 1F
(ii) According to the question,
Al3+ + 3e- → Al (27 g)
Electricity required to produce 27 g of Al = 3 F
Therefore, electricity required to produce 40 g of Al = \(\frac{3 \times 40}{27}\)F
= 4.44 F
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