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How much electricity in terms of Faraday is required to produce (i) 20.0 g of Ca from molten CaCl2. (ii) 40.0 g of Al from molten Al2O3.

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How much electricity in terms of Faraday is required to produce

(i) 20.0 g of Ca from molten CaCl2.

(ii) 40.0 g of Al from molten Al2O3.

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(i) According to the question,

Ca2+ + 2e- → Ca (40 g)

Electricity required to produce 40 g of calcium = 2 F

Therefore, electricity required to produce 20 g of calcium = \(\frac{2 \times 20}{40}\)F

= 1F

(ii) According to the question,

Al3+ + 3e- → Al (27 g)

Electricity required to produce 27 g of Al = 3 F

Therefore, electricity required to produce 40 g of Al = \(\frac{3 \times 40}{27}\)F

= 4.44 F

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