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19/01/2022 6:35 pm
Topic starter
How much charge is required for the following reductions:
(i) 1 mol of Al3+ to Al.
(ii) 1 mol of Cu2+ to Cu.
(iii) 1 mol of MnO4- to Mn2+.
1 Answer
1
19/01/2022 6:41 pm
(i) Al3+ + 3e- → Al
∴ Required charge = 3 F
= 3 × 96487 C
= 289461 C
(ii) Cu2+ + 2e- → Cu
∴ Required charge = 2 F
= 2 × 96487 C
= 192974 C
(iii) MnO4- → Mn2+
Mn7+ + 5e- → Mn2+
∴ Required charge = 5 F
= 5 × 96487 C
= 482435 C