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16/01/2022 6:35 pm
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Given the standard electrode potentials,
K+ /K = -2.93V, Ag+ /Ag = 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = -2.37 V, Cr3+/Cr = - 0.74V
Arrange these metals in their increasing order of reducing power.
1 Answer
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16/01/2022 6:37 pm
The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials increase in the order of K+ /K < Mg2+/Mg < Cr3+/Cr < Hg2+/Hg < Ag+ /Ag.
Hence, the reducing power of the given metals increases in the following order: Ag < Hg < Cr < Mg < K