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26/09/2021 4:40 pm
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What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistances 4 Ω, 8 Ω, 12 Ω, 24 Ω?
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26/09/2021 5:00 pm
(a) The highest resistance can be secured by connecting all the four coils in series.
∴ Equivalent resistance of series combination,
Rs= 4 + 8 + 12+ 24 = 48 Ω
Hence, the highest resistance that can be secured by given coils is 48 Ω.
(b) The lowest resistance can be secured by connecting all the four coils in parallel.
∴ Equivalent resistance of parallel combination,
\(\frac{1}{R_p}\) = \(\frac{1}{4}\) + \(\frac{1}{8}\) + \(\frac{1}{12}\) + \(\frac{1}{24}\)
= \(\frac{1}{2}\)
or Rp = 2 Ω
Hence, the lowest resistance that can be secured by given coils is 2 Ω.