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07/12/2020 3:12 pm
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Find out the following in the electric circuit given in figure:
(a) Effective resistance of two 8 Ω resistors in the combination,
(b) Current flowing through 4 Ω resistor,
(c) Potential difference across 4 Ω resistance,
(d) Power dissipated in 4 Ω resistor, and
(e) Difference in ammeter readings, if any.
1 Answer
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07/12/2020 3:18 pm
(a) Effective resistance, the two 8 Ω resistors in parallel,
RP = 8 x8/8+8 = 4Ω
(b) Req = 4 + Rp = 8Ω
So current through 4Ω = I = V/R = 8/8 = 1A
(c) Potential difference across resistance 4Ω = V1 = IR = 1 x 4 = 4 V
(d) Power dissipated = I2R = I2 x 4 = 4 w
(e) No difference, since the ammeters are connected in series and same current will pass through them, so reading of both ammeters will be same.