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26/09/2021 9:03 pm
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An electric heater of resistance 8 W draws a current of 15 A from the service mains for 2 hr. Calculate the rate at which heat is developed in the heater.
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26/09/2021 9:06 pm
Given: Resistance, R = 8 Ω, t = 2 hr, I = 15 A
Rate of heat developed, \(\frac{H}{t}\) = \(\frac{I^2RT}{t}\)
Power = I2R = (15)2 x 8 = 1800 W