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Coordinate Geometry
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08/06/2021 2:27 pm
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Find the values of y for which the distance between the points P (2, -3) and Q (10, y) is 10 units.
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08/06/2021 2:29 pm
Distance between (2, -3) and (10, y) is 10.
Using distance formula,
PQ = \(\sqrt{(10-2)^2 + (y+3)^2}\)
= \(\sqrt{(8)^2 + (y+3)^2}\)
Since PQ = 10
= \(\sqrt{(8)^2 + (y+3)^2}\)
Simplify the above equation and find the value of y.
Squaring both sides,
64 + (y + 3)2 = 100
(y + 3)2 = 36
y + 3 = ±6
y + 3 = +6 or y + 3 = −6
Therefore, y = 3 or -9.