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Find the coordinates of the points of trisection of the line segment joining (4, -1) and (-2, -3).

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Find the coordinates of the points of trisection of the line segment joining (4, -1) and (-2, -3).

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Let P (x1, y1) and Q (x2, y2) are the points of trisection of the line segment joining the given points i.e., AP = PQ = QB

Therefore, point P divides AB internally in the ratio 1:2.

x= (1×(-2) + 2×4)/3

= (-2 + 8)/3 = 6/3 = 2

y1 = (1×(-3) + 2×(-1))/(1 + 2)

= (-3 – 2)/3 = -5/3

P (x1, y1) = P(2, -5/3)

Point Q divides AB internally in the ratio 2:1.

x2 = (2×(-2) + 1×4)/(2 + 1)

= (-4 + 4)/3 = 0

y2 = (2×(-3) + 1×(-1))/(2 + 1)

= (-6 – 1)/3 = -7/3

The coordinates of the point Q is (0, -7/3)

This post was modified 3 years ago by Raavi Tiwari
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