Notifications
Clear all
Coordinate Geometry
1
Posts
2
Users
0
Likes
198
Views
0
10/06/2021 1:35 pm
Topic starter
Find the area of a rhombus if its vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order.
1 Answer
0
10/06/2021 1:40 pm
Let A(3, 0), B (4, 5), C(-1, 4) and D (-2, -1) are the vertices of a rhombus ABCD.
Length of diagonal AC = \(\sqrt{(3-(-1))^2 + (0-4)^2}\)
= \(\sqrt{16+16}\)
= \(4\sqrt{2}\)
Length of diagonal BD = \(\sqrt{(4-(-2))^2 + (5-(-1))^2}\)
= \(\sqrt{36+36}\)
= \(6\sqrt{2}\)
Area of rhombus ABCD = \(\frac{1}{2}\) x \(4\sqrt{2}\) x \(6\sqrt{2}\)
= 24 square units
This post was modified 3 years ago by Raavi Tiwari