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Check whether (5, -2), (6, 4) and (7, – 2) are the vertices of an isosceles triangle.

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Check whether (5, -2), (6, 4) and (7, – 2) are the vertices of an isosceles triangle.

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Let the points (5, -2), (6, 4), and (7, -2) are representing the vertices A, B, and C respectively.

AB = \(\sqrt{(6-5)^2 + (4+2)^2}\)

= \(\sqrt{(-1)^2 + (6)^2}\)

= \(\sqrt{37}\)

BC = \(\sqrt{(7-6)^2 + (-2-4)^2}\)

= \(\sqrt{(-1)^2 + (6)^2}\)

= \(\sqrt{37}\)

CA = \(\sqrt{(7-5)^2 + (-2+2)^2}\)

= \(\sqrt{(-2)^2 + (0)^2}\)

= 2

Here AB = BC = \(\sqrt{37}\)

This implies, whether given points are vertices of an isosceles triangle.

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