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Construct a triangle PQR in which QR = 6cm, ∠Q = 60° and PR – PQ = 2cm.
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21/07/2021 11:47 am
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Construct a triangle PQR in which QR = 6cm, ∠Q = 60° and PR – PQ = 2cm.
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21/07/2021 11:48 am
Construction Procedure:
The steps to draw the triangle of given measurement is as follows:
1. Draw a line segment of base QR = 6 cm
2. Measure and draw ∠Q = 60° and let the ray be QX
3. Take a compass and measure PR–PQ = 2cm.
4. Since PR–PQ is negative, QD will below the line QR.
5. With Q as centre and draw an arc at the point be D on the ray QX
6. Join DR
7. Now draw the perpendicular bisector of the line DR and the intersection point is taken as P.
8. Now join PR
9. Therefore, PQR is the required triangle.
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