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In Figure, ABC = 69°, ACB = 31°, find BDC.

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In Figure, ABC = 69°, ACB = 31°, find BDC.

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We know that angles in the segment of the circle are equal so,

∠BAC = ∠BDC

Now in the in ΔABC, the sum of all the interior angles will be 180°

∠ABC + ∠BAC + ∠ACB = 180°

Now, by putting the values,

∠BAC = 180°-69°-31°

∠BAC = 80°

∴ ∠BDC = 80°

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