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18/07/2021 12:37 pm
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In Figure, A,B and C are three points on a circle with centre O such that BOC = 30° and AOB = 60°. If D is a point on the circle other than the arc ABC, find ADC.
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18/07/2021 12:40 pm
It is given that,
AOC = AOB+BOC
AOC = 60°+30°
∴ AOC = 90°
It is known that an angle which is subtended by an arc at the centre of the circle is double the angle subtended by that arc at any point on the remaining part of the circle.
ADC = (\(\frac{1}{2}\))AOC
= \(\frac{1}{2}\) × 90° = 45°