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19/07/2021 12:46 pm
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In Figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find BAC.
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19/07/2021 12:47 pm
We know that the angles in the segment of the circle are equal.
∠ BAC = ∠CDE
Now, by using the exterior angles property of the triangle
In ΔCDE we get,
∠CEB = ∠CDE + ∠DCE
We know that ∠DCE is equal to 20°
∠CDE = 110°
∠BAC and ∠CDE are equal
∴ ∠BAC = 110°