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19/07/2021 1:23 pm
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If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side.
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19/07/2021 1:24 pm
First draw a triangle ABC and then two circles having diameter as AB and AC respectively.
We will have to now prove that D lies on BC and BDC is a straight line.
Proof:
We know that angle in the semi-circle are equal
∠ADB = ∠ADC = 90°
Hence, ∠ADB + ∠ADC = 180°
∴ ∠ BDC is straight line.
So, it can be said that D lies on the line BC.