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20/09/2020 7:43 pm
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In an estimation of bromine by Carius method, 1.6 g of an organic compound gave 1.88 g of AgBr. The mass percentage of bromine in the compound is …………
(Atomic mass, Ag = 108, Br = 80 g mol–1)
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20/09/2020 7:44 pm
If molar mass of compound is M
1.6/M = 1.88/188 = 0.01
so m = 160 gram/mole
Now %of bromine = 80/160 × 100 % = 50%