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A spherical balloon of radius 3 cm containing helium gas has a pressure of 48 × 10^–3 bar.

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A spherical balloon of radius 3 cm containing helium gas has a pressure of 48 × 10–3 bar. At the same temperature, the pressure, of a spherical balloon of radius 12 cm containing the same amount of gas will be ………….. ×10–6 bar.

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If volume of 3 cm balloon is = V

then volume of 12 cm radius balloon = 64V

So pressure will become 1/64 times = 1/64 × 48 × 10–3 bar = 750 × 10–3 bar

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