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The compound which shows metamerism is

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The compound which shows metamerism is

(1) C5H12

(2) C3H8O

(3) C3H6O

(4) C4H10O

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(4) C4H10O

Explanation:

(4) C4H10O will have different alkyl group attached with polyvalent functional group that's why show metamerism

CH3–CH2–O–CH2–CH3

CH3–O–CH2–CH2–CH3

(3) C3H6O

⇒ \(CH_3-\underset{O}{\underset{||}C}-CH_3\)

Only one arrangement possible so can not show metamerism.

(2) C3H8O

⇒ CH3–O–CH2–CH3

Only one arrangement possible so can not show metamerism.

(1) No polyvalent functional group in C5H12, so can not show metamerism.

This post was modified 7 months ago by admin
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