In [Ag (CN2)]-, the number of π bonds is : (a) 2 (b) 3 (c) 4 (d) 6

(c) 4 Explanation: In one – C ≡ N, No. of π bonds = 2 So in [Ag (CN2)]-, No. of π bonds = 2 ×2 = 4

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In [Ag (CN2)]^-, the number of π bonds is :

Chemical Bonding and Molecular Structure

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03/10/2020 10:56 am

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Shaneylee18

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In [Ag (CN₂)]^-, the number of π bonds is :

(a) 2

(b) 3

(d) 6

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03/10/2020 10:59 am

Freddie12

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Explanation:

In one – C ≡ N, No. of π bonds = 2

So in [Ag (CN₂)]^-, No. of π bonds = 2 ×2 = 4

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