Forum

Calculate the numbe...
 
Notifications
Clear all

Calculate the number of aluminium ions present in 0.051 g of aluminium oxide. (Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27 u)

1 Posts
2 Users
0 Likes
228 Views
0
Topic starter

Calculate the number of aluminium ions present in 0.051 g of aluminium oxide. (Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27 u)

1 Answer
0

Molar mass of Al2O3 = 2 × 27 + 3 × 16

= 54 + 48 = 102 g

∵ 102 g of Al2O3 contains

= 2 x 6.022 x 1023 Al3+ions

∴ 0.051 g of Al2O3 contains

= 2 x 6.022 x 1023/102 x 0.051

= 6.022 x 1020 Al3+ions

Share:

How Can We Help?