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The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

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The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

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Given that,

first term, a = 5

last term, l = 45

Sum of the AP, Sn = 400

Sn = n/2 (a+l)

400 = n/2(5+45)

400 = n/2(50)

Number of terms, n =16

As we know, the last term of AP series can be written as;

l = a+(n −1)d

45 = 5 +(16 −1)d

40 = 15d

Common difference, d = 40/15 = 8/3

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