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In an AP (i) Given a = 5, d = 3, an = 50, find n and Sn. (ii) Given a = 7, a13 = 35, find d and S13.

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In an AP

(i) Given a = 5, d = 3, an = 50, find n and Sn.

(ii) Given a = 7, a13 = 35, find d and S13.

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(i) Given that, a = 5, d = 3, an = 50

an = a +(n −1)d,

⇒ 50 = 5+(n -1)×3

⇒ 3(n -1) = 45

⇒ n -1 = 15

⇒ n = 16

Now, sum of n terms,

Sn = n/2 (a +an)

Sn = 16/2 (5 + 50) = 440

(ii) Given that, a = 7, a13 = 35

an = a+(n−1)d,

⇒ 35 = 7+(13-1)d

⇒ 12d = 28

⇒ d = 28/12 = 2.33

Now, Sn = n/2 (a+an)

S13 = 13/2 (7+35) = 273

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