The first multiple of 4 that is greater than 10 is 12.

Next multiple will be 16.

the series,

12, 16, 20, 24, …

All these are divisible by 4 and thus, all these are terms of an A.P. with first term as 12 and common difference as 4.

When we divide 250 by 4, the remainder will be 2.

Therefore, 250 − 2 = 248 is divisible by 4.

12, 16, 20, 24, …, 248

Let 248 be the n^th term of this A.P.

first term, a = 12

common difference, d = 4

a_n = 248

As we know,

a_n = a+(n−1)d

248 = 12+(n-1)×4

236/4 = n-1

59  = n-1

n = 60

Therefore, there are 60 multiples of 4 between 10 and 250.