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For what value of n, are the nth terms of two APs 63, 65, 67, and 3, 10, 17, … equal?

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For what value of n, are the nth terms of two APs 63, 65, 67, and 3, 10, 17, … equal?

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Given two APs as; 63, 65, 67,… and 3, 10, 17,….

Taking first AP,

63, 65, 67, …

First term, a = 63

Common difference, d = a2−a1 

= 65−63 = 2

We know, nth term of this A.P. = an = a+(n−1)d

an= 63+(n−1)2 = 63+2n−2

an = 61+2n ………………. (i)

Taking second AP,

3, 10, 17, …

First term, a = 3

Common difference, d = a2 − a1 

= 10 − 3 = 7

We know that,

nth term of this A.P.

= 3+(n−1)7

an = 3+7n−7

an = 7n−4 ……………….. (ii)

Given, nth term of these A.P.s are equal to each other.

Equating both these equations, we get,

61+2n = 7n−4

61+4 = 5n

5n = 65

n = 13

Therefore, 13th terms of both these A.P.s are equal to each other.

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