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Find the sum of first 15 multiples of 8.

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Find the sum of first 15 multiples of 8.

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The multiples of 8 are 8, 16, 24, 32…

First term as 8 and common difference as 8.

a = 8

d = 8

S15 = ?

Sn = n/2 [2a+(n-1)d]

S15 = 15/2 [2(8) + (15-1)8]

= 15/2[6 +(14)(8)]

= 15/2[16 +112]

= 15(128)/2

= 15 × 64

= 960

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