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Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (i) a = 7, d = 3, n = 8, an = ..... (ii) a = -18, d = ...., n = 10, an = 0

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Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P.

(i) a = 7, d = 3, n = 8, an = .....

(ii) a = -18, d = ...., n = 10, an = 0

(iii) a = ...., d = -3, n = 18, an = -5

(iv) a = -18.9, d = 2.5, n = ...., an = 3.6

(v) a = 3.5, d = 0, n = 105, an = ....

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(i) Given,

First term, a = 7

Common difference, d = 3

Number of terms, n = 8,

We have to find the nth term, an = ?

As we know, for an A.P.,

an = a+(n−1)d

Putting the values,

= 7+(8 −1) 3

= 7+(7) 3

= 7+21 = 28

Hence, an = 28

(ii) Given,

First term, a = -18

Common difference, d = ?

Number of terms, n = 10

Nth term, an = 0

As we know, for an A.P.,

an = a+(n−1)d

Putting the values,

0 = − 18 +(10−1)d

18 = 9d

d = 18/9 = 2

Hence, common difference, d = 2

(iii) Given,

First term, a = ?

Common difference, d = -3

Number of terms, n = 18

Nth term, an = -5

As we know, for an A.P.,

an = a+(n−1)d

Putting the values,

−5 = a+(18−1) (−3)

−5 = a+(17) (−3)

−5 = a−51

a = 51−5 = 46

Hence, a = 46

(iv) Given,

First term, a = -18.9

Common difference, d = 2.5

Number of terms, n = ?

Nth term, an = 3.6

As we know, for an A.P.,

an = a +(n −1)d

Putting the values,

3.6 = − 18.9+(n −1)2.5

3.6 + 18.9 = (n−1)2.5

22.5 = (n−1)2.5

(n – 1) = 22.5/2.5

n – 1 = 9

n = 10

Hence, n = 10

(v) Given,

First term, a = 3.5

Common difference, d = 0

Number of terms, n = 105

Nth term, an = ?

As we know, for an A.P.,

an = a+(n −1)d

Putting the values,

an = 3.5+(105−1) 0

an = 3.5+104×0

an = 3.5

Hence, an = 3.5

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