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Choose the correct choice in the following and justify: (i) 30th term of the A.P: 10,7, 4, …, is (A) 97 (B) 77 (C) −77 (D) −87 (ii) 11th term of the A.P. -3, -1/2, ,2 …. is

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Choose the correct choice in the following and justify:

(i) 30th term of the A.P: 10,7, 4, …, is

(A) 97 (B) 77 (C) −77 (D) −87

(ii) 11th term of the A.P. -3, -1/2, ,2 …. is

(A) 28 (B) 22 (C) – 38 (D) \(-48\frac{1}{2}\)

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(i) Given here,

A.P. = 10, 7, 4, …

we can find,

First term, a = 10

Common difference, d = a2 − a= 7−10 = −3

As we know, for an A.P.,

an = a +(n−1)d

Putting the values;

a30 = 10+(30−1)(−3)

a30 = 10+(29)(−3)

a30 = 10−87 = −77

Hence, the correct answer is option C.

(ii) Given here,

A.P. = -3, -1/2, ,2 …

Therefore, we can find,

First term a = – 3

Common difference, d = a2 − a1 = (-1/2) -(-3)

⇒(-1/2) + 3 = 5/2

As we know, for an A.P.,

an = a+(n−1)d

Putting the values;

a11 = 3+(11-1)(5/2)

a11 = 3+(10)(5/2)

a11 = -3+25

a11 = 22

Hence, the answer is option B.

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