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Find the area of a quadrant of a circle whose circumference is 22 cm.

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Find the area of a quadrant of a circle whose circumference is 22 cm.

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Circumference of the circle, C = 22 cm

Let the radius of the circle = r

As C = 2πr = 22,

R = 22/2π cm

= 7/2 cm

∴ Area of the quadrant = (θ/360°) × πr2

Here, θ = 90°

A = (90°/360°) × πrcm2

= (49/16) π cm2

= 77/8 cm2 

= 9.6 cm2

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