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Acids, bases and salt
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04/09/2021 11:54 am
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10 mL of solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise will be
(a) 4 mL
(b) 8 mL
(c) 12 mL
(d) 16 mL
1 Answer
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04/09/2021 11:57 am
Correct answer: (d) 16 mL
Explanation:
Since 10 ml of NaOH requires 8 mL of HCl.
20 ml of NaOH require ............ HCl.
Let X be the amount of HCl required to neutralize the 20 ml of NaOH.
X = (20 × 8)/10
X = 16 ml