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Each step has a rise of 1/4 m and a tread of 1/2 m. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions The houses of a row are numbered consecutively from 1 to 49. Show that there is a value of x such that the sum of the numbers of the houses preceding the house numbered x is equal to the sum of the numbers of the houses following it. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions A ladder has rungs 25 cm apart. figure. The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Which term of the AP: 121, 117, 113, . . ., is its first negative term? [Hint: Find n for an < 0] 3 years ago Priya123 class 10 cbse ncert arithmetic progressions In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato and other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions 200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on. In how many rows are the 200 logs placed and how many logs are in the top row? 3 years ago Priya123 class 10 cbse ncert arithmetic progressions A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A of radii 0.5, 1.0 cm, 1.5 cm, 2.0 cm, ……… as shown in figure. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees 3 years ago Priya123 class 10 cbse ncert arithmetic progressions A sum of Rs 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is Rs 20 less than its preceding prize, find the value of each of the prizes. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs. 200 for the first day, Rs. 250 for the second day, Rs. 300 for the third day, etc., the penalty for each succeeding day being Rs. 50 more... 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Find the sum of the odd numbers between 0 and 50. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Find the sum of first 15 multiples of 8. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Find the sum of first 40 positive integers divisible by 6. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions If the sum of the first n terms of an AP is 4n - n^2, what is the first term (that is S1)? What is the sum of first two terms? 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Show that a1, a2 …, an, … form an AP where an is defined as below (i) an = 3+4n (ii) an = 9−5n 3 years ago Priya123 class 10 cbse ncert arithmetic progressions If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Find the sum of first 22 terms of an AP in which d = 7 and 22nd term is 149. 3 years ago Priya123 class 10 cbse ncert arithmetic progressions The first and the last term of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum? 3 years ago Priya123 class 10 cbse ncert arithmetic progressions Page 1 / 4 1 2 3 4 Next Share: Super Globals Requests: Server: Options and Features route: community use_home_url: url: https://eanshub.com/community/ pageid:187 default_groupid: 3 2022 How Can We Help? Δ Home About Us Contact Us Privacy Policy Term of Use Copyright © 2020 Eanshub All Rights Reserved
