Last seen: Jun 14, 2021
From the given two figures, we can see their corresponding angles are different or unequal. Therefore they are not similar.
(i) Similar (ii) Similar (iii) Equilateral (iv) (a) Equal (b) Proportional
As we can see from the given figure, the first step is 1/2 m wide, 2nd step is 1m wide and 3rd step is 3/2m wide. 1/2, 1, 3/2, 2, …….. Volume of s...
Row houses are numbers from 1,2,3,4,5…….49. First term, a = 1 Common difference, d=1 Let us say the number of xth houses can be represented as; ...
Distance between the rungs of the ladder is 25cm. Distance between the top rung and bottom rung of the ladder is = m = = cm = 250cm Therefore, ...
From the given statements, we can write, a3 + a7 = 6 ……………….(i) a3 ×a7 = 8 ………………..(ii) By the nth term formula, an = a+(n−1)d Third term, ...
Given the AP series is 121, 117, 113, . . ., Thus, first term, a = 121 Common difference, d = 117-121= -4 an = a+(n −1)d Therefore, an = 121...
The distances of potatoes from the bucket are 5, 8, 11, 14…, which is in the form of AP. 10, 16, 22, 28, 34,………. Hence, the first term, a = 10 and...
We can see that the numbers of logs in rows are in the form of an A.P.20, 19, 18… First term, a = 20 and common difference, d = a2−a1 = 19−20 = -1 ...
Perimeter of a semi-circle = πr P1 = π(0.5) = π/2 cm P2 = π(1) = π cm P3 = π(1.5) = 3π/2 cm Where, P1, P2, P3 are the lengths of the semi-circ...
1, 2, 3, 4, 5………………..12 First term, a = 1 Common difference, d = 2−1 = 1 Sn = n/2 [2a +(n-1)d] S12 = 12/2 [2(1)+(12-1)(1)] = 6(2+11) = 6(1...
Let the cost of 1st prize be Rs. P. Cost of 2nd prize = Rs. P − 20 And cost of 3rd prize = Rs. P − 40 common difference as −20 and first term as...
First term as 200 and common difference as 50. a = 200 and d = 50 Penalty that has to be paid if contractor has delayed the work by 30 days = S30 ...
The odd numbers between 0 and 50 are 1, 3, 5, 7, 9 … 49. First term, a = 1 Common difference, d = 2 Last term, l = 49 l = a+(n−1) d 49 = 1+(...
The multiples of 8 are 8, 16, 24, 32… First term as 8 and common difference as 8. a = 8 d = 8 S15 = ? Sn = n/2 [2a+(n-1)d] S15 = 15/2 [2(8...
The positive integers that are divisible by 6 are 6, 12, 18, 24 …. First term is 6 and common difference is 6. a = 6 d = 6 S40 = ? Sn = n/2 ...
Given, Sn = 4n−n2 First term, a = S1 = 4(1) − (1)2 = 4−1 = 3 Sum of first two terms = S2= 4(2)−(2)2 = 8−4 = 4 Second term, a2 = S2 − S1 ...
(i) an = 3+4n a1 = 3+4(1) = 7 a2 = 3+4(2) = 3+8 = 11 a3 = 3+4(3) = 3+12 = 15 a4 = 3+4(4) = 3+16 = 19 We can see here, the common difference ...
Given that, S7 = 49 S17 = 289 We know, Sum of n terms; Sn = n/2 [2a + (n – 1)d] S7= 7/2 [2a +(n -1)d] S7 = 7/2 [2a + (7 -1)d] 49 = 7/2 [...
Given that, Second term, a2 = 14 Third term, a3 = 18 Common difference, d = a3−a2 = 18−14 = 4 a2 = a+d 14 = a+4 a = 10 = First term S...