Last seen: Jun 14, 2021
The basic objective of the foreign policy of Independent India was non-alignment, i.e. the American and Soviet alliances.
The Bhilai Steel Plant was viewed as an important sign of the development of modem India after Independence.
Development of heavy industries. The building of large dams.
The new state of Andhra Pradesh came into existence on 1 October 1953.
He was a veteran Gandhian who went on a hunger strike demanding the formation of Andhra state to protect the interests of Telugu speakers.
Forests and agriculture.
Education and health.
Nathuram Godse disagreed with Gandhiji’s conviction that Hindus and Muslims should live together in harmony.
All Indians above the age of 21 would be allowed to vote in state and national elections.
The Indian Constitution was adopted on 26 January 1950.
(i) - (c) (ii) - (a) (iii) - (e) (iv) - (b) (v) - (d).
Given, ABC is an isosceles triangle. ∴ AB = AC ⇒ ∠ABD = ∠ECF In ΔABD and ΔECF, ∠ADB = ∠EFC (Each 90°) ∠BAD = ∠CEF (Already proved) ∴ ΔABD ...
Given, CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively. 2s.png ...
Given, ABC and AMP are two right triangles, right angled at B and M respectively. (i) In ΔABC and ΔAMP, we have, ∠CAB = ∠MAP (common angles) ∠AB...
Given, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Consider the figure below, 2s.png In ΔABE and ΔC...
Given, altitudes AD and CE of ΔABC intersect each other at the point P. (i) In ΔAEP and ΔCDP, ∠AEP = ∠CDP (90° each) ∠APE = ∠CPD (Vertically opp...
Given, ΔABE ≅ ΔACD. ∴ AB = AC [By CPCT] ……………….(i) And, AD = AE [By CPCT] ………………(ii) In ΔADE and ΔABC, dividing eq.(ii) by eq(i), AD/AB = AE/...
Given, S and T are point on sides PR and QR of ΔPQR 2s.png And ∠P = ∠RTS. In ΔRPQ and ΔRTS, ∠RTS = ∠QPS (Given) ∠R = ∠R (Common angle) ...
In ΔPQR, ∠PQR = ∠PRQ ∴ PQ = PR ………………(i) Given, QR/QS = QT/PR Using equation (i), we get QR/QS = QT/QP ………….(ii) In ΔPQS and ΔTQR, by equ...
2s.png In ΔDOC and ΔBOA, AB || CD, thus alternate interior angles will be equal, ∴ ∠CDO = ∠ABO Similarly, ∠DCO = ∠BAO Also, for the two ...