Last seen: Jan 13, 2022
(4) Be Explanation: BeSO4 - Soluble in water Be(OH)2 - Insoluble in water Structure of BeO is Hexagonal Wurtzite.
(3) (b) only Explanation: (a) In transition metals on moving down the group higher oxidation states are more stable due to smaller size of atoms, ...
(4) Li2O, Na2O2 and KO2 Explanation: On heating in excess air Li form oxide sodium form peroxide while K, Rb, Cs form superoxide.
(4) Visible Explanation: In hydrogen spectrum maximum lines of Balmer series lies in visible region.
(2) (a), (b), (c) and (d) Explanation: All statements are correct.
(3) (a), (c) and (d) Explanation: (a) For ideal gas U and H are function of Temperature U = f/2 nRT (c) CP –CV = R (d) ΔU = CVdT for all proce...
(1) O2– > F– > Na+ > Mg2+ Explanation: O2– F– Na+ Mg2+ Z 8 9 11 12 No. of e– 10 10 10 10 ...
(1) Actinoids and Group 4 Explanation: 89Ac → 103Lr Belongs to actinoids series and they all belongs to 3rd group. So atomic no. 101 element is ...
Light of wavelength 6000 × 10–10 m passes through a single slit of width 0.6 × 10–4 m. Find height of highest order of minima on both side central max...
PV = nRT PΔV + VΔP = 0 ΔV = - ΔP/P V ...(i) In second case PΔV = -nRΔT ΔV = nRΔT/P ....(ii) equating (i) and (ii) nRΔT/P = - ΔP/P V ...
f = D2 - d2/4D = 1002 - 402/4(100) = (100 + 40)(100-40)/4(100) = 21 cm P = 1/f = 100/21 = N/100 N = 476.19
(2) 8.5 MeV Explanation: Binding energy = (ΔM)C2 = (ΔM) 931 put the value of ΔM BE = 8.5 MeV
(1) 1.67 Explanation: ΔP = (B)Δv/v = B x 3 ΔL/L Putting the value of ΔP and B we get ΔL/L x 100 = 1.67
(2) 0.75 A/m Explanation: M = CBext/T Putting the value we get N = 0.25 A/m
(2) 10 rad s–1 Explanation: From energy conservation 1/2Iω2 = Uin - Ur = – MB cos60º – (–MB) MB/2 = 1/2Iω2 20 x 4/2 = 1/2(0.8)ω2 100 =...
(1) 2 Explanation: Moment of inertia of disc is given by I = MR2/2 = [ρ(πR2)t]R2 I ∝ R4 I1 / I2 = (R2/R4)4 16/1 = α4 α = 2
(4) 91 kmh–1 Explanation: Frequency appeared at wall fw = 330/(330 - v).f ....(1) f' = 330 + v/330.fw = (330 + v)/(330 - v).f 490 = 330 + /...
(2) 1/√2 Explanation: v0/ve = √(Gm/r)/√2Gm/r = 1/√2
(0.1) (200) + (0.05) (400) = (0.15)T T = 20 + 20/0.15 = 800/3 = 266.67
(1) 4.15 gm Explanation: Fb - mg = ma Fb = m(g + a) = 4/3πr3ρg = m(g + a) m = 4/3π(1)g = m(980 + 9.8) m = 4.15