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A ball of mass 200g falls from a height of 5 meters. What is its kinetic energy when it just reaches the ground?

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A ball of mass 200g falls from a height of 5 meters. What is its kinetic energy when it just reaches the ground?

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Mass = 200 g = 0.2kg

Height = 5m

Initial velocity, u = 0

Acceleration due to gravity, g = 9.8 m/s2

Final velocity, v

Using third equation of motion,

v2 – u2 = 2gs

v2 = 98

Kinetic energy = \(\frac{1}{2}\) mv2

Kinetic energy = (\(\frac{1}{2}\))(0.2)(98) = 9.8J

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