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07/10/2020 12:07 pm
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The ΔfH° for CO2(g), CO(g) and H2O(g) are -393.5, -110.5 and -241.8 kJ/mol respectively, the standard enthalpy change (in kJ) for the reaction
CO2 (g) + H2 (g) → CO(g) + H2O(g) is :
(a) 524.1
(b) 41.2
(c) -262.5
(d) -41.2
1 Answer
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07/10/2020 12:20 pm
(b) 41.2
Explanation:
ΔH = Σ[ΔfH° products] - Σ[ΔfH° reactants]
ΔH° = [ΔfH°(CO)(g) + ΔfH°(H2O)(g) - [ΔfH°(CO2 (g) + ΔfH°H2 (g)]
= [-110.5 + (-241.8)] - [-393.5 + 0]
= 41.2 kJ