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06/10/2020 10:55 am
Topic starter
The heat of reaction for :
C10H8(s) + 12O2(g) → 10CO2(g) + 4H2O(l)
at constant volume is –1228.2 kcal at 25°C. The heat of reaction at constant pressure and same temperature is:
(a) -1228.2 k cal
(b) -1229.3 k cal
(c) -1232.9 k cal
(d) -1242.6 k cal
1 Answer
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06/10/2020 11:00 am
(b) -1229.3 k cal
Explanation:
ΔE = -1228.2 k cal = -1228.2 x 103 cal
ΔH = ΔE + ΔnRT
= -1228.2 x 103 + (-2)(2)(298)
= -1229392 cal
= -1229.392