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06/10/2020 4:29 pm
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One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, then final temperature of the gas is (Cv = 20 J/K)
(a) 100 K
(b) 150 K
(c) 195 K
(d) 255 K
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06/10/2020 4:31 pm
(b) 150 K
Explanation:
Since the gas expands adiabatically (i.e., no change in enthalpy) so the heat is totally converted into work.
For the gas, Cv = 20 J/K. Thus, 20 J of heat is required for 1° change in temperature of the gas.
Heat change involved during the process i.e., work done = 3 kJ = 3000 J.
Change in temperature = 3000/20 K = 150K
Initial temperature = 300 K
Since, the gas expands so the temperature decreases and thus final temperature is 300 - 150 = 150 K