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For the reaction, 2Cl(g) → Cl2 (g), the signs of ΔH and ΔS respectively, are:

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For the reaction, 2Cl(g) → Cl2 (g), the signs of ΔH and ΔS respectively, are:

(a) +, -

(b) +, +

(c) –, –

(d) –, +

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(c) –, –

Explanation:

2Cl(g) → Cl2 (g)

Entropy is decreasing (–ve) in the reaction. Further the reaction is exothermic since a bond is being formed, i.e., ΔH is also –ve.

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