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05/10/2020 5:47 pm
Topic starter
Combustion of glucose takes place according
to the equation:
C6H12O6+ 2O2 → 6CO2 + 6H2O, ΔH = -72 k cal
The energy required for production of 1.6 g of glucose is [molecular mass of glucose is 180 g]
(a) 0.064 k cal
(b) 0.64 k cal
(c) 6.4 k cal
(d) 64 k cal
1 Answer
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05/10/2020 5:49 pm
(b) 0.64 k cal
Explanation:
Formation of glucose will be the given by reaction taking place in reverse direction.
6CO2 + 6H2O + 72Cal → C6H12O6 + 6O2
For production of 180 g of glucose, heat energy is 72 k cals.
So required heat for 1.6 g of glucose
= 72/180 x 1.6 = 0.64 k cal