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06/10/2020 1:07 pm
Topic starter
Calculate change in internal energy if ΔH = – 92.2 kJ, P = 40 atm and ΔH = –1L.
(a) – 42 kJ
(b) – 88 kJ
(c) + 88 kJ
(d) + 42 kJ.
1 Answer
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06/10/2020 1:12 pm
(b) – 88 kJ
Explanation:
ΔH = -92.2 kJ, P = 40 atm, ΔV = -1 L
Using ΔH = ΔE + PΔV
=> ΔE = ΔH - PΔV
= (-92.2kJ) - (40 atm) (-1L) x R/R
= – 92.2 kJ + (40 atm L) × (8.314 JK-1 mol-1)/(0.0821 (atm LK-1 mol-1)
= – 92200 J + 4050.66 J = – 88149.34 J
= – 88.149 kJ > – 88 kJ